Recent content by fluutekies

Seriously, i don't think WikiLeaks is the right place at the moment to publish the withheld data. If i had ounce again a document of public interest, i would sent it (anonymously) to cryptome.org ! "... Cryptome welcomes documents for publication that are prohibited by governments...

The wastewater treatment for Fukushima according to the above presentation would involve in principle: 1. water/oil-separator 2. solids separation from the water-phase by decanter/centrifuges (see page 12) 3. remaining solids in the clear water are removed by membrane-filtration (page 13...

https://www.physicsforums.com/showpost.php?p=3267742&postcount=4952 The pdf document: http://www.osti.gov/bridge/servlets/purl/93598-H1kI7u/webviewable/93598.pdf I've designed & operated an inorganic wastewater treatment unit for some years: the volumes are not the problem, but the...

Dave Lochbaum's analyses: Fukushima Dai-Ichi Unit 1: The First 30 Minutes: http://allthingsnuclear.org/post/5835907657/fukushima-dai-ichi-unit-1-the-first-30-minutes Fukushima Dai-Ichi Unit 2: The First 60 Minutes...

Cryptome has some more hi-res pictures from the series of 70: http://cryptome.org/eyeball/daiichi-npp15/daiichi-photos15.htm

Fukushima Daiichi Nuclear Power Station First Floor of Turbine Building of Unit 1, May 6th, 2011)

That are my figures: 1331 used + 204 unused = 1535 assemblies in SFP4 http://www.iaea.org/newscenter/news/tsunamiupdate01.html [Fukushima Nuclear Accident Update (22 March 2011, 18:00 UTC)]

I think I got it: Under normal conditions enriched boric acid H3BO3 probably is -even at its much higher price and limited availability- the boron compound of choice in a nuclear power plant: highest concentration B-10, lowest concentration of accompanying elements (only O and H) and high...

Why should they use enriched B-11? It would be very expensive and scarce. Natural occurring boron contains 20% B-10 with 80% B-11. Boric acid H3BO3, Borax Na2B2O7 and even Boron trioxide B2O3 are bulk chemicals and very cheap. (I don't think TEPCO needs high grade qualities anymore ...) An...

Zr + 2H2O --> ZrO2 + 2H2 + 14.6*106 J/kg Zr Source: http://www.galcit.caltech.edu/~jeshep/fukushima/ShepherdFukushima30April2011.pdf page 62 BTW: Great source! Edit: another source http://oa.upm.es/718/1/Miguel_Angel_Jimenez_Garcia.pdf dH = 576 kJ/mol Zr My Spanish is not good, but...

Please be advised that @tep_co is some sarcastic parody...

Here a summary after 7 weeks: http://allthingsnuclear.org/post/5173479472/fukushima-7-week-update Here a translation of the Plant Tour Video: http://www.houseoffoust.com/fukushima/5_3_vid.html

Lots of pre-quake images here: http://www.houseoffoust.com/fukushima/phototour.html

Then calculate amount U-235 needed and use fission energy.

I assume you mean I-131 from fission of U-235. The fission yield is: 2.878% (wikipedia) Specific activity: 4598.8 TBq/g http://www.wolframalpha.com/input/?i=Iodine-131 x Bq I-131 = x * 4.5988*10^-15 g I-131 Does that answer your question?