Recent content by foo9008

I defined y-axis as the axis that is up , which is not into the book ...

sorry , i misunderstood something . Clear now . For second question , i let the horizontal axis as x-axis ( which is also the neutral axis) ...So , the moment of inertia is about the neutral axis , which is only Ixx only , right ? We don't have to consider Iyy ( moment about vertical axis ...

Homework Statement In the first photo , i was told that the I represent the moment of inertia about the neutral axis ... But , in the 2nd photo , i found that the author calculate the moment of inertia about the x-axis (parallel to neutral axis ) and y -axis ( perpendicular to neutral axis) ...

are they wrong ?

10^6 = MPa , 10^3 = kN , are they wrong ?

total force = pressure act on steel (area of steel) + pressure on concrete (area of concrete) = pressure act on steel (area of steel) + pressure on concrete (10 area of steel)

sorry , i made a typo , it should be (175x10^6)(Area of steel) + (14x10^6)(10 Area of steel ) = 1000x10^3 Area of steel = 3.174(mm^2) , is it correct now ?

Or each of the steel and concrete received forces of 1000kN ?

anyone ?

Anyone can response?

or there's something wrong with my calculation ?

Homework Statement here's the question , Part of solution was given , but not the final ans . I have tried to do , but i need someone to verify my ans . Homework EquationsThe Attempt at a Solution Since , stress of steel is 12.5 times of stress of concrete . The max allowable stress in steel...

Just to double check, the 65.2mm is the maximum t, not minimum t, am I right?

ok , when using force = 220kPa , i found that w = 65.2mm, but when i use P = 50kN , w = 14.8mm , when using P = 90kPa , my t = 24mm , why is it so ? if so , then it's maximum t , right ?

So how should I proceed?