Recent content by Fooze

I believe the point was to just give you an idea of how it would go, not do the exact problem for you. However, yes... x2 is 0 since it's treated as a constant.

Hey all... I've got a good friend of mine who's graduating this May from University of Alaska Fairbanks with a degree in Mechanical Engineering. He's also getting married this July and moving to Indiana (around Warsaw) to be with his wife while she finishes up a degree. My question is...

Yes, that is what I was figuring... I was just hoping to prove my professor wrong. ;) If anyone has any other thoughts though, please do let me know!

Homework Statement I know that the ratio test can be proved using the geometric series knowledge, but I'm looking for a way to prove the ratio test without the geometric series at all. The reason is that I'm proving the geometric series convergence with the ratio test, and my professor...

Looks like your f'(x) is right. However, yeah, I'd say your f''(x) has some issues. Remember that 1/sqrt(x) = x^(-1/2). If you remember that, it should be easier to take your derivative, just remember to do the product rule again. This means that d/dx (1/sqrt(x)) = d/dx (x^(-1/2)) =...

I don't trust myself at all solving integrating factor problems in my head. I had issues in the beginning of the semester with them... and it's just recently that I've been able to do them properly at all. ;) But thanks so much for your help... I should be able to get it from there!

I haven't tried it yet on paper (don't have any handy for another 45 minutes or so) but should I be thinking like a u(t) = y(t)2? That will leave me with a u' + u = t, I think? Then it's linear and really easy with an integrating factor. Is that the right thought?

Homework Statement This is just a nonlinear differential equation. All I have to do it solve it, though it is an initial value problem as well. 2*y*y' + y^{2} = t Initial value: y(0) = -1. The Attempt at a Solution This should be easy, but it doesn't seem easily...