Recent content by frazdaz
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Equilibrium temperature of a mixture
Qin = extra thermal energy the steam has over the milk + heat to be released when the steam condenses Qout = heat lost from the steam + heat gained by milk- frazdaz
- Post #3
- Forum: Introductory Physics Homework Help
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Equilibrium temperature of a mixture
Homework Statement Homework Equations Q = m c \Delta T \\ Q = m L_v \\ Q_{in} = Q_{out} The Attempt at a Solution m_s c_s (100 - 8) + m_s L_v = m_s c_s (100 - T) + m_m c_s (T) \\ 5778.06 + 33900 = 5778.06 - 62.805 T + 418.7 T \\ 33900 = 355.895 T \\ ∴ T = 95.25°C Answer should...- frazdaz
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- Equilibrium Equilibrium temperature Mixture Temperature
- Replies: 3
- Forum: Introductory Physics Homework Help
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Kirchhoff's Laws: Homework Solutions Check
Well that's good news. And, yeah, I guess it's just intended to help with the maths side of things.- frazdaz
- Post #5
- Forum: Introductory Physics Homework Help
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Kirchhoff's Laws: Homework Solutions Check
The answers have I1 and I2 with opposite signs. I get them both as positive.- frazdaz
- Post #3
- Forum: Introductory Physics Homework Help
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Kirchhoff's Laws: Homework Solutions Check
Homework Statement Homework Equations \sum I_{in} = \sum I_{out} \sum \epsilon = \sum pd The Attempt at a Solution Can anyone identify any mistakes in these? Probably signs I = I_1 + I_2 12=4I_1 +3I 5=4I_1 - 2I_2 12-5=2I_2+3I- frazdaz
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- Laws
- Replies: 4
- Forum: Introductory Physics Homework Help
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Centripetal Acceleration Quick Question
The point at which the automobile leaves the bridge is when it's no longer in contact with the bridge i.e. there is no normal force. There's no force preventing it going through the bridge because it isn't in contact with it.- frazdaz
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- Forum: Introductory Physics Homework Help
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Rolling Ball and angle of incline
How would it slip if the linear acceleration smaller than the RHS? I can picture the ball accelerating so quickly that it begins to slip, but not the other way around.- frazdaz
- Post #14
- Forum: Introductory Physics Homework Help
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Rolling Ball and angle of incline
Does that work as an inequality? i.e. object won't slip providing as long as this holds true a \leq \alpha r- frazdaz
- Post #11
- Forum: Introductory Physics Homework Help
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Rolling Ball and angle of incline
Ahhh, of course. Thank you! I take it the tangential acceleration is in the direction of the linear velocity? And is the radial acceleration just the centripetal acceleration?- frazdaz
- Post #7
- Forum: Introductory Physics Homework Help
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Rolling Ball and angle of incline
I've just never seen that before. mgrsin\theta = \frac{7mr^2}{5} \frac{g}{5} sin\theta = \frac{7r}{25} Does it want it in terms of r or have I gone wrong? \theta = sin^{-1}(\frac{7r}{25})- frazdaz
- Post #5
- Forum: Introductory Physics Homework Help
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Rolling Ball and angle of incline
Like this? (found from one of your posts) a_t= \alpha r- frazdaz
- Post #3
- Forum: Introductory Physics Homework Help
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Rolling Ball and angle of incline
Homework Statement A uniform solid sphere rolls down an incline without slipping. If the linear acceleration of the centre of mass of the sphere is 0.2g, then what is the angle the incline makes with the horizontal? Repeat for a thin spherical shell. Homework Equations \sum \tau = I \alpha...- frazdaz
- Thread
- Angle Ball Incline Rolling Rolling ball
- Replies: 14
- Forum: Introductory Physics Homework Help