Recent content by Frozen Stair

Simon, the difference in time constants is *very* obvious -it can't be accounted for by experimental error. Strangely, when charging, the time constant calculated from T=RC is accurately depicted in the graph ("nearly" completely charged at 5T). But when discharging, there's a dramatic...

Homework Statement This isn't a problem from a textbook, but it is homework. For a lab in class, we worked with simple RC circuits on breadboards. The strange thing I noticed is that the capacitor always charges faster than it discharges. I know that the Time constant should be T=RC, so I...

No, thank you so much! :)

Oh, I think I see now. Instead of Throcky being pushed so that he is at a constant speed, he has an acceleration. And, by the work-energy theorem, W = ΔK, so this would suggest that the exercise has such a greater value for work than the example because the speed is increasing.

I see what you mean. F=2w at θ=1.11, which is already quite far. But what do you mean by the "extra work"?

Hi. :) When θ is small...in the example, the force would be very small (F=wtanθ). In the exercise, it would be 2w. I was thinking about this, but I can't figure out how exactly this connects to the work that is done.

1. Homework Statement This problem is connected to an example in the textbook. Here's some of the key info from the example, first of all: You are appointed to push your cousin Throckymorton in a swing. His weight is w, the length of the chains is R, and you push Throcky until the chains...