since the numerator has to be positive for large positive x's and negative for negative x's, (x-4)^3/(x^2-1)(x-3) satisfies the requirements that you gave, but when I plug it into my calculator the graph does not show the necessary requirements
I also know that tan^-1(x) has two horizontal asymptotes, do I then incorporate x^3 into the numerator of the equation? Also thanks a lot for all your help.
since vertical asymptotes arise from 0 being in the denominator, would 1/(x^2-1)(x-3) satisfy having three vertical asymptotes? and wouldn't they be -1, 1, and 3
For the life of me I cannot figure out this problem: give an example of a function that has two horizontal asymptotes and three vertical asymptotes. Any help on this topic would be greatly appreciated.