Recent content by G153
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G
Ive a problem? It so easy but I can't get it
9.8 m/s^2 ?- G153
- Post #9
- Forum: Advanced Physics Homework Help
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G
Ive a problem? It so easy but I can't get it
Is it different because the velocity changes right? For the first p I got p=68*10.6=720.8. So then how am I supposed to find the second one that you were talking about?- G153
- Post #7
- Forum: Advanced Physics Homework Help
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G
Ive a problem? It so easy but I can't get it
So in this case do I use that formula and calculate: Δp= F (found with acceleration) * 1.02s? So is Δp the force that the problem is asking me?- G153
- Post #5
- Forum: Advanced Physics Homework Help
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G
Ive a problem? It so easy but I can't get it
I'm not sure we've been using this definition. But eventually, how can I use it? Shouldn't I find force?- G153
- Post #3
- Forum: Advanced Physics Homework Help
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G
Ive a problem? It so easy but I can't get it
PLEASE HELP A 68 kg acrobat jumps from a 2 meter ledge on to a trampoline. If the acrobat bounces off the trampoline with a velocity of 10.6 m/s over a contact time of 1.02 seconds, what force did the trampoline exert on the acrobat?Well I ve tried to do it multiples times, using the formula...- G153
- Thread
- Force Homework Physics
- Replies: 10
- Forum: Advanced Physics Homework Help