Recent content by G153

  1. G

    Ive a problem? It so easy but I can't get it

    Is it different because the velocity changes right? For the first p I got p=68*10.6=720.8. So then how am I supposed to find the second one that you were talking about?
  2. G

    Ive a problem? It so easy but I can't get it

    So in this case do I use that formula and calculate: Δp= F (found with acceleration) * 1.02s? So is Δp the force that the problem is asking me?
  3. G

    Ive a problem? It so easy but I can't get it

    I'm not sure we've been using this definition. But eventually, how can I use it? Shouldn't I find force?
  4. G

    Ive a problem? It so easy but I can't get it

    PLEASE HELP A 68 kg acrobat jumps from a 2 meter ledge on to a trampoline. If the acrobat bounces off the trampoline with a velocity of 10.6 m/s over a contact time of 1.02 seconds, what force did the trampoline exert on the acrobat?Well I ve tried to do it multiples times, using the formula...
Back
Top