Recent content by Gabri110

Yeah, my bad, I had forgotten to divide by 2 the ladder operators...

Oh my... Thank you, I feel so dumb right now...

Using the ladder operators I can easily compute ##E = \langle H\rangle = \hbar \omega n##, so I can find the amplitude of the classical oscillator, as ##E = \frac{1}{2} m \omega^2 x_{max}^2##, thus, ##x_{max} = \sqrt{\dfrac{2 E}{m \omega^2}} = \sqrt{\dfrac{2\hbar n}{m \omega}}##. The...