Difference between expectation value of ##x## and classical amplitude of oscillation for an harmonic oscillator

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Homework Help Overview

The discussion revolves around the difference between the expectation value of position, ##\langle x \rangle##, and the classical amplitude of oscillation, ##x_{max}##, for a harmonic oscillator. Participants are exploring the implications of their calculations using ladder operators and wavefunctions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss their calculations of energy and expectation values using ladder operators, questioning the time dependence of ##\langle x \rangle## compared to classical solutions. Some express uncertainty about their results and seek clarification on specific terms in the problem statement.

Discussion Status

The discussion is active, with participants sharing their findings and questioning their assumptions. Some have identified potential errors in their calculations, while others are considering different interpretations of the problem, particularly regarding the comparison of amplitudes.

Contextual Notes

There is a mention of confusion regarding the term "factor" in the exercise statement, which may influence the understanding of the problem. Participants are also reflecting on the implications of their results and the need for careful consideration of definitions and calculations.

Gabri110
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Homework Statement
The oscillator is in the state ##\lvert \psi (t)\rangle = \dfrac{1}{\sqrt{2}} \left( e^{-i (n-\frac{1}{2})\omega t}\lvert n-1 \rangle + e^{-i (n+\frac{1}{2})\omega t}\lvert n \rangle \right)##.

Calculate the amplitude of oscillation of a classical oscillator of this frequency and energy ##E = \langle\psi (t)\rvert H \lvert\psi (t)\rangle## and show that it differs from your result for ##\langle\psi (t)\rvert x \lvert\psi (t)\rangle## by a factor independent of ##n##.
Relevant Equations
##\lvert \psi (t)\rangle = \dfrac{1}{\sqrt{2}} \left( e^{-i (n-\frac{1}{2})\omega t}\lvert n-1 \rangle + e^{-i (n+\frac{1}{2})\omega t}\lvert n \rangle \right)##
Using the ladder operators I can easily compute ##E = \langle H\rangle = \hbar \omega n##, so I can find the amplitude of the classical oscillator, as ##E = \frac{1}{2} m \omega^2 x_{max}^2##, thus, ##x_{max} = \sqrt{\dfrac{2 E}{m \omega^2}} = \sqrt{\dfrac{2\hbar n}{m \omega}}##.

The expectation value of ##x## can be also easily computed using the ladder operators. I find ##\langle x\rangle = \sqrt{\dfrac{2\hbar n}{m \omega}}\cos{\omega t}##. This is clearly a problem, as I find that ##\langle x\rangle## is time dependent (and the classical solution isn't!). The difference is ##x_{max} - \langle x\rangle = \sqrt{\dfrac{2\hbar n}{m \omega}} (1 - \cos{\omega t})##, which isn't independent of ##n##, as the exercise statement says.

Can someone help me find where I have made a mistake?
 
Last edited:
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Reread the question. What does “factor” mean?
 
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vela said:
Reread the question. What does “factor” mean?
Oh my... Thank you, I feel so dumb right now...
 
Gabri110 said:
I find ##\langle x\rangle = \sqrt{\dfrac{2\hbar n}{m \omega}}\cos{\omega t}##.
I got a slightly different result for the expression inside the square root. Of course, I might be the one making a mistake. But I calculated it two ways: using the ladder operators and using the known wavefunctions for the harmonic oscillator.

Also, since ##\langle x\rangle## oscillates harmonically, I wonder if it would be more appropriate to compare the amplitude, ##x_{max}##, of the classical oscillator with the amplitude of the ##\langle x\rangle## oscillation. I'm not sure.
 
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Yeah, my bad, I had forgotten to divide by 2 the ladder operators...
 
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