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Quantum Mechanics: Expected momentum of a real wavefunction
I conclude that I am either wrong, or that <p> = 0. I'm inclined to the former, but the latter makes sense, because if I was integrating around the origin (say, from -5 to 5 instead), it would cancel.- galaxyrocker
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- Forum: Advanced Physics Homework Help
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Quantum Mechanics: Expected momentum of a real wavefunction
Homework Statement Given the wavefunction, \psi(x) = Cx for 0 < x < 10 and \psi(x) = 0 for all other values. What is the normalization constant of C? I got \sqrt{3/1000}. What is <x>? I got 30/4. What is <p>? Here is where I'm confused.Homework Equations \langle p \rangle = C^2...- galaxyrocker
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- Mechanics Momentum Quantum Quantum mechanics Wavefunction
- Replies: 4
- Forum: Advanced Physics Homework Help