Recent content by Ganar

Alright thank you I'll keep working at it if I have anymore questions I'll go ahead and ask them. Thanks again for the help!

So that means I would get a set of equations like so: F14= k(q1q4)/(3-x)^2 F24=k(q2q4)/(2-x)^2 F34=k(q3q4)/(x)^2 F54=k(q5q4)/(x)^2 And I set these all equal to each other and will end up with a quadratic expression then use the quadratic formula to solve the problem?

[b]1. Five charges of 1.00 μC magnitude are placed in a row, each charge being 1.00 m distant from its neighboring charges. If all chargers are positive, what is the magnitude in N/C, of the electric field at the position of charge 4? A) 0 B)2.13x10^-2 C)3.25x10^-3 D)3.25x10^3 E)2.13x10^4...