Recent content by gator

Given a, b are constants and lim x approch 1, a root x+3 - b all over x-1 equals 1. Find a and b No clue how to answer this, but this is what I think i can do a) get rid of the sqrt b) apply limit See, the problem is I have to unknows so i don't know what to do

so like (e^x - 1)(e^x2 -e^x +1) so I now have e^x2 - e^x +1

L'Hopital's rule?

and a quick question on limits lim x right arrow 0 e^3x -1 / e^x -1 since anything to the root 0 is 1 you get 1-1/1-1 = 0

lol yea! now are you any good at continuity? I have a question using the def. of continuity to determine the points at which the function is no continuous and indicate whether the discontinuity is removable or not f(x) = HUGE bracket (x+1)absolute value x-2 all over 2 sqrt x+1 x<0...

ok, i have you until the last sentsnce. if "k" is an interger, then the amount of VA's i could have is endless. Im also a little lost on what i should write down on my assignment by the way, thanks for all this help

sin2x is zero when x=1/2 pi ? since that would mean sin = pi which would be zero on the denom

So my VA is x=pi ?

sin = zero @ pi (180* on unit circle) yep, covered limits. But in our notes he covers finding the VA without using limits (weird i know) so I am not sure

The only thing that would have the denom zero would be zero (sin2(o)) = 0 but that would cause the nom to become zero

im trying to say f(x)= 2x / sin2x

Question: Find the Vertical Asymptote if any f(x)=[tex}\frac{2x}{\sin2x}[\tex] Im somewhat lost, I cross multi and get 1/2 although my friends tell me this just equals 1. Any ideas? err...cant get the cool math symbol things to work...

Im in calculus 1 and need some help Question: Find the vertical asymptotes for… F(x) = x^3 + 8 / x^2 –4 I got a va of –2 F(x) = 2x/ sin2x I got a va of 1 Find the limit Lim tan^2 2x/ x^2 x-0 I got 4 as my answer Lim x^2 –4 / (x + 2 )^2 x- (-2) I got –4/0 = no limit...

so for question 1(i) the answer is...tan t = 1.87* ? 1(ii) 1/cos Pie/12 - sinx/cosx pie /12 1 - sin2x = cos2x. so... 1 - sin x / cosx (pie/12)^2 = (1/cosx (pie/12))^2 ahhh...im so lost #2...dont have a sweet clue...i have no notes on this...kinda clueless #3 is it cos225...

Ive been given very little notes from my teahcer, and can't do these. looked online, but its was no use. 1. Using the identities to find the vales of each expression (no calc.) (i) sin t = 15/17 , cos t = 8/17 find remaining trig functions (ii) sec^2 Pie/12 - tan^2 Pie/12 2. Find exact...