Recent content by gaywaiha
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Integration of y=(1+0.25x^2)^0.5
Sorry about that. The interval is (0≤x≤2).- gaywaiha
- Post #8
- Forum: Calculus and Beyond Homework Help
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Integration of y=(1+0.25x^2)^0.5
Guys thank you very much. I am sorry that I substituted 2tanx and forgot to type the 2. But now I finally found the answer by separate 1/cos^3x into (1/cosx)(tanx)' and work it out using integration by part. Thank you- gaywaiha
- Post #6
- Forum: Calculus and Beyond Homework Help
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Integration of y=(1+0.25x^2)^0.5
Homework Statement I am told to find out the length of he curve y=¼x^2 Homework Equations The length of the curve should be ∫√(1+¼x^2)dxThe Attempt at a Solution I substituted tanx and got ∫2/cos^3x dx So how could I continue and work out the solution? Should I use integration by part, or I...- gaywaiha
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- Integration
- Replies: 7
- Forum: Calculus and Beyond Homework Help