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gentzen's latest activity
gentzen
replied to the thread
I
Violation of Bell Inequality with unentangled photons
.
You are missing Your sign measurement operators ##S_x## and ##S_p## are no longer representable by a single state, hence you have to...
Thursday, 3:15 PM
gentzen
replied to the thread
I
Violation of Bell Inequality with unentangled photons
.
Yes, of course. I guess what you didn't understand is that your ##|\alpha|^2S_x+|\beta|^2S_p## is missing those interference terms...
Thursday, 2:32 PM
gentzen
replied to the thread
I
Violation of Bell Inequality with unentangled photons
.
This is an observable. Your ##S_x## and ##S_p## were observables too. Maybe to clarify, we have ##\alpha=\cos(\theta)## and...
Thursday, 1:11 PM
gentzen
replied to the thread
I
Modern View of Quantum Phenomena
.
Suppose you start with the state ##|\psi_{\alpha,\beta}\rangle=\alpha |z+\rangle+\beta|z-\rangle##. Then there is a measurement that...
Thursday, 1:06 PM
gentzen
replied to the thread
I
Violation of Bell Inequality with unentangled photons
.
The state is entangled, but pines-demon tried to get rid of the continuous measurement outcomes, to be closer to typical Bell...
Thursday, 12:58 PM
gentzen
replied to the thread
I
Violation of Bell Inequality with unentangled photons
.
You mean, because they are not normalizable? But they are well defined in a suitable space of distributions, and one can form their...
Thursday, 12:41 PM
gentzen
replied to the thread
I
Violation of Bell Inequality with unentangled photons
.
$$(\alpha|x\rangle+\beta|p\rangle)(\alpha^*\langle x|+\beta^*\langle p|)=|\alpha|^2|x\rangle\langle x|+|\beta|^2|p\rangle\langle...
Thursday, 12:31 PM
gentzen
replied to the thread
I
Violation of Bell Inequality with unentangled photons
.
If you define it like this, then ##S_x## and ##S_p## are already matrices (or rather operators), basically ##S_x=\int_0^\infty dx\...
Thursday, 11:52 AM
gentzen
replied to the thread
I
Violation of Bell Inequality with unentangled photons
.
It just makes it easy for me to see that the state is not time invariant. With the signs of your state, I would have been a bit less...
Thursday, 10:55 AM
gentzen
replied to the thread
I
Violation of Bell Inequality with unentangled photons
.
Because the spin in the normal "measurements showing Bell's inequality violations" is constant in time. The position is not, which on...
Thursday, 10:50 AM
gentzen
replied to the thread
I
Violation of Bell Inequality with unentangled photons
.
Because starting with |p>|-p> corresponds to the EPR description of the experiment (the total momentum is zero). In principle, one...
Thursday, 10:33 AM
gentzen
replied to the thread
I
Modern View of Quantum Phenomena
.
It measures the spin of the particle in some specific direction, as it was initially before the bending of the beam. (I am still a bit...
Thursday, 10:21 AM
gentzen
replied to the thread
I
Modern View of Quantum Phenomena
.
If I have two entangled particles in "two beams" with known fixed direction, then I want to measure their spin, not the spin of two...
Thursday, 8:45 AM
gentzen
replied to the thread
I
Violation of Bell Inequality with unentangled photons
.
Now I understand what you wanted to say: The initial state ##|\psi\rangle## for the EPR experiment can be assumed to be ψ... I guess...
Thursday, 8:30 AM
gentzen
replied to the thread
I
Violation of Bell Inequality with unentangled photons
.
Maybe read what you wrote exactly, see whether it makes any sense to you. And then ask yourself, how anybody who wants to have a serious...
Thursday, 7:13 AM
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