Recent content by gigidy-goo

Thanks Doc Al, I'll try that and see how I go

Hi all, I'm really stumped at this question five of my assignment. Could anyone please give me some help? I don't even know where to start. Thanks

Ah, right well that's a tad embarrassing. I have it now so thanks to everyone for helping out, I squared 'x' inside the bracket instead of outside. That's great so there is only a local min and not a max? And the behaviour of this function increases as it tends towards infinity, would...

Ok so by squaring x before, I'm still not getting the right numbers... -1^2 = -1 3.-1=-3 -3-8=-11 Where are I going wrong?

I think I'm way off here. How did you get x = -1, y = -5? I've tried it a few different ways and end up with different answers; For x = -1 3(-1^2)-8 -1^2(3)-8 This is probably quite simple stuff but if I know how to do this I can get the rest

Hi hallsofivy, Thanks for replying. I just meant my attempt left me with a situation where x=0,y=-8. But I'm not sure why my line doesn't look like an upward slope as per the graph?

Hi armolinasf Thanks for replying The slope I drew came from changing x to -2,-1,0,1,2,3,etc so I ended up with a line starting at, x=-3,y=-26 x=-2,y=-20 x=-1,y=-14 x=0,y=-8 x=1,y=-1 x=2,y=4 x=3, y=10. x=4,y=16 It is going upward you're right but it doesn't look like...

Hello to all. I'm having a few problems and would love to know how to do the following. 1. f(x) = 3x^2-8 2. Find the function's zeros, local max/min and the function's behaviour 3. My attempt at drawing the function ended with a downward curve intercepting at y=-8, x=0 But a...