Recent content by gispiamp

BACKGROUND: I calculated a spin-1/2 ptl. with const magnetic field. I thought that, as time goes by, the spin should align to the direction of the magnetic field, because the energy of that state is lowest energy. but, the spin vector(expectation value) just rotates around the direction...

to get higer order of R, I expand exponential term to 1st order but they doesn't give correct order. I_4's coefficient is R^(-3) and Integral gives R^(5) but this order vanished and R^(3) and R^(2) remains. that's the problem let C=2R/a_0, x=2r/a_0, (dummy r zero to n) I_n gives...

Hm.. using Hydrogen atom's e.ft, |100>, and calculating <100|H`|100> in spherical coords. I tried that way before I ask. but It doesn't gives same answer. main Integration is I_n= \int {r^n}{e^(\frac{r}{a_0})} and n=4,2,1. with some coeff. It doesn't give R^2 and a_0^3 Is that wrong...

how could you calculate it? please explain it to me

This Prob is from Shankar, 17.2.3 "we assumed that the proton is a point charge e. If the proton is a uniformly dense charge distribution of radius R, the interaction is modified as V(r)= -2(e)^2/(2R) + (er)^2/(2(R)^3) r<R = -e^2/r r>R Calculate 1st Order shift in the ground-state...

thx for your Q&A!