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    How Does Gauss' Law Apply to Electric Flux Through a Cube's Surface?

    I think I got it. Total Flux of Cube = Q (charge) / ε = (10x10^-9) / (8.85x10^-12) 1129.94 / 6 = 188.32 N m^2 / C. This is the answer I was given. Thanks for the help!
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    How Does Gauss' Law Apply to Electric Flux Through a Cube's Surface?

    I'm... not sure? The point charge is in the center of the cube itself, so... no?
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    How Does Gauss' Law Apply to Electric Flux Through a Cube's Surface?

    Homework Statement A 10 nC point charge is at the center of a 2 m x 2 m x 2 m cube. What is the electric flux through the top surface of the cube?Homework Equations Electric Flux = E x A x cosθ Electric Flux = ∫E x dA = Q(inside)/ε E (point charge) = kq/r^2 where k = 1/(4pi ε) The Attempt at...
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    Nonuniform Circular Motion: Old-Fashioned Amusement Park Ride

    I drew the wrong kind of diagram (I misinterpreted the question), which is why I ended up getting confused. I managed to figure it out after I read your post. Thanks for the help!
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    Nonuniform Circular Motion: Old-Fashioned Amusement Park Ride

    Sorry for having my first post be a question, I guess. I'm just confused as to how to do this since I've never really been one for word problems. I can't really type in... tex(?) either. Oh well, here we go: Homework Statement In an old-fashioned amusement park ride, passengers stand inside...
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