Recent content by GoldWing

Thank you so much! :smile:

That makes sense and I wasn't sure when that would come into play, so would I take the sin of 60 since it's an equilateral triangle and multiply it by the force? And add the forces from both wires?

I considered the direction of to be going up (according to the right hand rule, current goes out of page, filed goes counterclockwise so the force is up) , and please correct me if I'm wrong.

I'm not sure what you mean. Wasn't I supposed to use 2.08A as my currents?

Homework Statement Three long parallel wires are a distance L = 5.71 cm from one another. (Looking at them, they are at three corners of an equilateral triangle.) The top wire has a diameter of 1.8 mm and is made of copper; it is suspended in air due to the magnetic forces from the bottom two...

Homework Statement Assuming R = R' in the network shown above, determine the net resistance between the points a and c. Express your answer as a number times R. b. Assuming R = R', determine the net resistance between the points a and b. c. Now suppose R' = 2.5R, and find the net resistance...

I'm sorry, I thought I had stated this. The question is: What is the net capacitance? If 26.0 V is applied across the whole network, calculate the voltage across each capacitor. Use the numerical values of capacitance given, C1 = 2.98 μF, C2 = 4.15 μF, and C3 = 1.64 μF.

Homework Statement Capacitors C1 and C2 are connected in series and this combination is connected in parallel with capacitor C3. Homework Equations Q=CV Ceq=C1+C2+C3 equivalent capacitance for capacitors in parallel 1/Ceq=1/C1+1/C2+1/C3 equivalent capacitance for capacitors in series The...