Recent content by GoodQuestion

Shouldn't ##\hbar## change also, because there's a meter in there as well? Assuming the value of KG en second stays the same, shouldn't this lead to ##\varepsilon0##" becomes ##\varepsilon0 \cdot 1,1{^3}## ?

I was wondering: what would be the value of Vacuum Permettivity in the case 1 meter (say 1m") would be defined as the distance we nowadays see as 1,10 meters. At first this looks easy: ##\varepsilon0 = 8.8541878128 \cdot 10{^{12}}## F / m with normal meters so ##\varepsilon0" = \varepsilon0...