Recent content by Govind_Balaji

I think x1, x2 are position rather than displacement. Displacement is the change in position, isn't it?

Amazing!, how to work on the last equation? Is this correct? $$dW=\vec F \cdot \vec v dt$$ $$\frac{dW}{dt}=\vec F \cdot \vec v$$[Can I just divide the equation by ##dt## like this one?\ $$\text{Power}=\vec F \cdot \vec v$$ Is this also right? \begin{align*}\\\frac{dW}{dt}&=\vec F \cdot \vec...

I have one doubt. What is the correct definition of work? My books say ##W=\vec F \cdot \vec x## But ##W=\int F(x) dx## seems more reasonable. Also what if force is given as a function of time.

Horrible! Calculus is not in the portion. anyway I know some basics of it and figured out the answer as 32-8=24 J. Thank you very much.

Homework Statement A force ##F=4x## is applied on an object. What is work done to move it from ##x_1=2m## to ##x_2=4m##? A)12 J B)24 J C)32 J D)48 J Homework EquationsThe Attempt at a Solution The displacement, ##x=4-2=2m## Force, ##F=4x=4 \times 2=8N## Work ##W=\vec F \cdot \vec x=8 \times 2...

I am actually doing a science project for an exhibition. It's tomorrow and I think of substituting cell phone microwaves with radio waves along with some wires and conductors. It's a bit difficult to explain here. I just had a doubt whether it's a flaw. So I just made sure it's complete.

Suppose I have a transmitter and receiver and my friend in the next room also has it. Can we both talk with each other with radio waves as we do in cell phone. I know we can't talk if he is several miles apart. But if he is just in the next room, can we communicate?

Yes I know just lazy to do that because when I miss 1° accuracy, I may get very strange results.

I guess there must be a printing error in the question like may be the angles changed or like that

Even I tried what Simon said with a simulator called GEOGEBRA. I get the same result.

It seems a difficult work. Are there any thing to do with Theoretical geometry.

Homework Statement ABC is a triangle. The bisector of the exterior angle at B and the bisector of ∠C intersect each other at D. Then prove that ∠D=90°-(∠A/2) Homework Equations The Attempt at a Solution I guess I want to prove an untrue thing because by drawing a diagram and...

I think of doing something like a seismometer. But I am very confused on what concept to use and how to use

No I got this today evening and searched till now and I got this idea of asking now only.

The science fair is after 1-2 months but I should submit a report not exceeding 300 words what I will do in the project tomorrow morning to my teacher. Now it's 10pm. Please give me ideas as soon as possible(Before 30min from now)