Recent content by GrahamCU

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    Trig Identities for Refraction

    bump for help. is this an identity? [2cosasinb]2 = sin2a sin2b
  2. G

    Trig Identities for Refraction

    Ok, I actually just made a mistake typing the question in here. I fixed it now, and posted pictures of my work so you can see how I got there. The last line (now correct in first post) should have been show how [2cosasinb]2 = sin2a sin2b Thanks for your help :)
  3. G

    Trig Identities for Refraction

    ok thanks, I'll double check my work again, and if it doesn't work out, post my complete work to see
  4. G

    Trig Identities for Refraction

    Homework Statement The problem is essentially (I've rephrased it, but this is what it is asking) show that [ (2n1cosa) / (n2cosa + n1cosb) ]2 is equal to (sin2a sin2b) / (sin2(a+b)cos2(a-b)) where these are for refraction through materials and satisfy n1sina=n2sinb 2. The...
  5. G

    How Do You Determine if Two Values Agree?

    SOLVED:Agreement of 2 values This is my first post, so I hope this is the write section for it.. How do you check if 2 values agree with each other (I've seen it called the "comparison test", but I can't find what I'm looking for by google-ing that). For example, you have x1=563+-12...
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