Recent content by Grim Arrow

Can't believe it. Can't believe how blind I was.. Offcourse. I mean, I know this, I was just blinded somehow. Too much thought in your head can make you dumb enough to not see the truth. It is just an ordinary HPF! Thank you, Genji! Thanks, Jony! Thanks, Berkeman!

Basicaly I stated that when the polarity is reversed the HPF will act as a HPF, but for V- (Looking at a sine wave this V- would be the minimum voltage)

Oh, so now as I think of it, "and the output voltage polarity" that might be the case. Normaly this would mean that when the signal shifts polarity, the output voltage will fall(because it forms Low Pass filter) but I think V+ decreasing is like to say the negative voltage is increasing and this...

But isn't the point of HPF that if the frequency decrease, Xc will increase and more voltage will fall across the capacitor and progressively less across the resistor which results in a progressively decreasing amplitude of the output signal. Thus HPF won't pass signals below the cutoff...

So I wanted to make something clear. I really posted too much threads this week, but that's for the purpose of learning. So a CE Amplifier has a blocking capacitor which together with the input impedance forms a high pass filter. But what I think is this filter is a high pass one only when the...

Thanks once again!

Thanks! And the input resistance is given by R1||R2 + the transistor's input resistance(Ube/Ib)?

Thanks!

I found this in a site called "Learningaboutelectronics" and it says I can use this table to choose a coupling cap for my frequency needs. This sure solves some of my problems, but I need to know how they got these values.

Are there any particular formulas?

How do I determine the value of a blocking capacitor for say this circuit: What I mean is, sure Cin must behave like a short circuit at working frequency, but something tells me there is more to the choice of a coupling capacitor than this.

Thanks everyone, your help is very helpful!

Okay, I understand now. My thanks to all for the help!

Okay, Jony130, I've looked at your loop rule equations, and I understand it, but isn't it too long and complicated to use it for setting up the bias? I mean, sure there must be an easier way. Say if Vbe=0,7V, Ve=1V, Vcc=20V, the voltage we need at the collector node of Q1 will be Ve + Vce(sat)...

Thank you! I've got one more question if you don't mind. I don't get how this circuit can compensate heat. I mean I believed I do, but things got complicated. What I know is that when temperature increases, Ic1 will slightly decrease the collector voltage. This will reduce the potential...