Recent content by H=Leo

Oh I see... Thanks a lot for the help!

And also, is the mass of an object is directly proportional to the energy it takes up? I am assuming the pot is 0.6 kg and the oil is 1.2 kg, therefore divide 214 kJ by 18 pieces and times 6 for the energy taken up for the pot, and times 12 for the energy taken up for the oil. I don't know...

So what you are saying is that the pot and the oil don't both absorb 214kJ of energy, instead they divide 214kJ up and both take up portions of that energy?

To keep everything safe, pressure regulators are displaced in mines. It is used to regulate the air pressure there so that miners working extended hours won't feel sick. ( There are quite a number of cases before where miners fell ill because of this.) The principle behind this is just like the...

I don't know but I guess I have to apply the formula c=E/ΔT where c is the heat capacity, E is Joules, and ΔT is the temperature difference I know that if there is 214kJ of energy supplied to the pot, the final temperature of the pot would be Let x degree Celsius be the temperature difference...

I recently encountered this problem in class "A glass pot of mass 0.6kg contains 1.2kg of oil at 15 degrees Celsius. If 214kJ of energy is supplied to it, what is the final temperature of the pot and oil? ( The specific heat capacity of glass is 700 J kg-1 °C-1, and the specific heat capacity of...