How Do You Calculate the Final Temperature of a Glass Pot and Oil?

[H=Leo]

I recently encountered this problem in class
"A glass pot of mass 0.6kg contains 1.2kg of oil at 15 degrees Celsius. If 214kJ of energy is supplied to it, what is the final temperature of the pot and oil? ( The specific heat capacity of glass is 700 J kg^-1 °C^-1, and the specific heat capacity of oil is 2200 J kg^-1 °C^-1 )"
Please help!
Any help would be greatly appreciated!

 

[Suraj M]

Give it a try yourself, first.
Do you know any equations which involve change in temperature and heat required to do so?
If you do, equate the heat supplied to the sum of that equations for both the oil and container, remember final temperature for both the constituents must be equal

 

[H=Leo]

I don't know but I guess I have to apply the formula
c=E/ΔT
where c is the heat capacity, E is Joules, and ΔT is the temperature difference

I know that if there is 214kJ of energy supplied to the pot, the final temperature of the pot would be

Let x degree Celsius be the temperature difference

700=214000/x
∴x=305 degree Celsius.

Final temperature
Initial temperature + x
=15+305
=320 °C

However, I don't know how to relate the pot to the oil and find out the final temperature of two objects with different heat capacities.
Thanks.

 

[Suraj M]

c=E/ΔT

I don't see mass there? It should be in there.

700=214000/x
∴x=305 degree Celsius.

Final temperature
Initial temperature + x
=15+305
=320 °C

However, I don't know how to relate the pot to the oil and find out the final temperature of two objects with different heat capacities.

the heat=214000 should be equated to sum of the heat absorbed by the oil and container.

c=E/ΔT

This is just your $E_1$ find $E_2$ which is for the oil then add and equate to heat supplied.

 

[SteamKing]

I don't know but I guess I have to apply the formula
c=E/ΔT
where c is the heat capacity, E is Joules, and ΔT is the temperature difference

I know that if there is 214kJ of energy supplied to the pot, the final temperature of the pot would be

Let x degree Celsius be the temperature difference

700=214000/x
∴x=305 degree Celsius.

Final temperature
Initial temperature + x
=15+305
=320 °C

However, I don't know how to relate the pot to the oil and find out the final temperature of two objects with different heat capacities.
Thanks.

Given the units of specific heat capacity (J / kg / °C), don't you think it's reasonable to assume that the mass of a substance figures into how much energy it takes to change its temperature?

 

[H=Leo]

So what you are saying is that the pot and the oil don't both absorb 214kJ of energy, instead they divide 214kJ up and both take up portions of that energy?

 

[Suraj M]

Precisely, equate it, you'll get an equation with 1 variable, solve.

 

[H=Leo]

And also, is the mass of an object is directly proportional to the energy it takes up?
I am assuming the pot is 0.6 kg and the oil is 1.2 kg,
therefore divide 214 kJ by 18 pieces and times 6 for the energy taken up for the pot, and times 12 for the energy taken up for the oil.
I don't know whether if it is really that straight-forward, but I am assuming it is.

 

[Suraj M]

No, it's not, you also have to consider their specific heats.
Don't complicate it,Leo.. you have your equation$E=mcΔT$from this find $E_1~and~ E_2$ add and equate to 214000, don't worry about how the energy is divided, you don't need to.
Try to form the equation, i described above.

 

[H=Leo]

Oh I see... Thanks a lot for the help!