Well I finally figured it out. The equation ended up being:
9.8 m/s2 * 1000 kg/m3 * (VolumeStyrofoam + 5.67E-6The volume of platinum) = 1.3426 Nweight of platinum + (9.8m/ss * 95kg/m3density of Styrofoam * VolumeStyrofoam)
Which is then:
9800V + .0559421= 1.3426 + 931V
8869V = 1.2870058...
Homework Statement
The first part of the question states this: If we want to buoy a 0.137 kg solid platinum object in water with an attached string from above, what is the tension required to support the piece of platinum?
The correct answer is: 1.28 Newtons. I got this by subtracting the...