Recent content by HadManySons

I had wondered how to go about that, since you had mentioned it earlier. Thanks for pointing that out.

Well I finally figured it out. The equation ended up being: 9.8 m/s2 * 1000 kg/m3 * (VolumeStyrofoam + 5.67E-6The volume of platinum) = 1.3426 Nweight of platinum + (9.8m/ss * 95kg/m3density of Styrofoam * VolumeStyrofoam) Which is then: 9800V + .0559421= 1.3426 + 931V 8869V = 1.2870058...

Homework Statement The first part of the question states this: If we want to buoy a 0.137 kg solid platinum object in water with an attached string from above, what is the tension required to support the piece of platinum? The correct answer is: 1.28 Newtons. I got this by subtracting the...