Recent content by HanningWu

a) Yes, it is because mercury is available, as mentioned in many papers. But I am afraid this explanation seems a little trivial... b) Also, since the critical temperature of mercury is lower than the boil point of helium(4.2K), it still can be regarded as a high critical temperature?

Because mercury has a low melting point? What are the advantages of mercury in the isotope effect experiment? Can we use some other materials?

Sorry, I didn't see that difference. Thanks to point it out.

But...what I find in wikipedia(Weak isospin, the second paragraph) is that The weak isospin conservation law relates the conservation of T3; all weak interactions must preserve T3. It is also conserved by the other interactions and is therefore a conserved quantity in general. (Weak isospin is...

Does "the parity of the wave-function combining the two particle" mean the parity valued (-1)L, where L is the orbital quantum number?

Since I can't simply multiply the parity of the Lambda bayon and the photon, how can I calculate the parity of the final state?

Thank you so much! Problem solved. :biggrin:

I found an article, titled Electromagnetic Decay of the Σ0(1385) to Λγ , in the arXiv telling that the reaction Σ0→Λ+γ can happen through electromagnetic interaction. However, if I examine the conservation of parity. Parity on the left side is even(P(Σ0)=+), but that on the right side is...