Recent content by Harenil

The curvature due to photon energy would be extremely negligible, and thus, very very hard to measure. It's hard enough to measure the curvature from a massive object.

Consider your charge. You multiplied by (-1), but what are the units of that? Units of fundamental charge, which is NOT 1 C. EDIT: Lol, What he said ^

Right, try adding the integral of E dot dl or dr (whatever you guys call it.) into your arsenal.

I think the best way to approach this problem is with Gauss's law. You need to set an arbitrary charge (it will vanish in the end.). Use a cylinder as your Gaussian surface. Hope this helps

Quite fascinating, thank you very much.

I was under the impression that you could not have a naked singularity unless a/M was greater than 1. And if a/M = 1, then there was a single event horizon, but an event horizon none the less.

Thank you very much, I will have to check that out. So I am correct that an extremal black hole will possesses zero temperature and entropy?

So I was calculating the temperature for a extremal Kerr black hole. G2*M2 = a2, where a = J/m. Using T = kappa / 2 /Pi... I'm assuming this is the correct approach. But my question is... The surface gravity of an extremal Kerr black hole appears to be zero, leading to a zero temperature...