Recent content by harmeet_angel

Homework Statement If a kayaker doubles her power output, and the resistive force due to the water remains same, by what factor does her speed changes(provided that her initial speed was constant, and is v0)? Homework Equations Power = Fd/t The Attempt at a Solution So, first I...

maybe if classical is an old computer or a car then quantum mechanics would be a new computer or an airplane?

oops, that was a typo umm.. yea, i think your way''s right

6.8 N umm.. i think this isn't possible though

thnx a lot for assuring me.. and for #4 N-W = centripetal force m.(normal a)-mg = m(v^2/r) but normal a=7g so (v^2/r)=7g-g so r=(v^2/g) =382.23 m and N = 7 x 9.81 x 80 kg I think i am wrong, perhaps because in the question it says "acceleration of the pilot".. so that...

it's on centripetal force and gravitation problems.. wonderin if anyone can provide me answers such that i can compare mine here's the assignment http://www.geocities.com/cheemaharmeet/assignment.jpg mine are { 1. 8N; 2. 1.97 hr; 3. 7.9E3 m/s 4. 382.26 m, 5.49E3 N 5. 8E-10 N 6...

yea, because she is not being pushed by her seat so shez weightless.. other situation..a free falling elevator, with some thing in it, and that thing would be weightless

thanks a lot to all! and, as for how did i get there<assuming that me's right> centripetal force is the resultant, and there must be something that provides it... in this case, the car is pushed up by the road, down by the gravity and the net force is keeping the car in the circle as normal...

Homework Statement An automobile moves at constant speed over a hill with a radius of 18 m. At the top of the hill, the drivers notices that she barely remains in contact with the seat. find the speed of the vehicle. Homework Equations Using Newton's second lay, and centripetal force...

umm.. you can use something that uses: pressure or fluid principles Springs and electricity <I wonder about this one, like how you would be able to convert electricity to mechanical energy.. even if you could, you would have to do deal with complexities, perhaps.. not sure though> so...

woaw! thanks. So, that would be acceleration = (g(2-1) )/ total mass = g/3 and Net force on 1 kg = (g/3) [N] and T = W+ (g/3) =g+(g/3) and so the reading would be = g (1+(1/3)) am i right? I think i am using the right technique but math may be wrong..

oops, and though the picture shows that the scale measuring hook is attached to 2 kg mass, however, since I made this question.. so, yea, actually the mass on the right should say 2 kg

you should had this formula in your relevant equations thingy: radius = diameter /2 2 is a number, and has uncertainty of 0 so, use division rule

A pulley Problem Homework Statement So, in the diagram attached one mass is 1 kg, and the other one is 2 kg. and what would be reading on the scale Homework Equations F=ma The Attempt at a Solution I think this is very much like an elevator problem where the elevator is moving...

1. Homework Statement Car A is towing car B. Both cars have the same mass ma = mb = 1000 kg. Car A has four-wheel drive, and the static coefficient of friction between its tires and the road is µs = 1.00 Neglect any friction force acting on car B. Car A is accelerating at 1m/s/s. Calculate...