When I write A\text{rect}_{\Delta}(f-f_0) I mean it's a rect signal with amplitude A (usually a constant), duration Δ and is centered in f_0.
So in this case there are 2 rect signals, one centered in -4W on the left and the other one centered in +4W on the right. Both have a duration of 4W...
Hi everyone!
I was trying to solve an old exercise but in a different way. It asks to find the signal x(t) given the graphs of |X(f)| and arg[X(f)]. Please refer to the attachment.
My stategy this time is as follows:
1) find D(f) by deriving |X(f)|
2) antitransform D(f) and get d(t)
3)...
I thought of breaking the equation in 2 pieces:
\underbrace{\mathcal{F}^{-1}[ \frac{1}{16}f e^{j2\pi \frac{1}{144W}f }]}_{\text{1st addend}}+ \underbrace{\mathcal{F}^{-1}[\frac{3}{8}We^{j2\pi\frac{1}{144W}f } ]}_{\text{2nd addend}}
I know that \mathcal{F}[\delta(t-t_0) ]=e^{j2\pi t_0 f}...
Sorry I'm late in replying, I was little busy.
So X(f) should be:
X(f)=
\left\{
\begin{array}{ll}
(\frac{1}{16}f +\frac{3}{8}W)e^{-j(-\frac{2\pi}{144W}f)} &, \text{ for -6W $\leq$ f $\leq$ -2W} \\...
So you're saying the Amplitude should be something like:
\frac{1}{16}f +\frac{3}{8}W \mbox{, for -6W \leq f \leq -2W}
-\frac{1}{16}f +\frac{3}{8}W \mbox{, for 6W \leq f \leq 2W} \right.
As for the PHASE, it should be:
\phi(f)=-\frac{\pi}{72W}f
Which by the way means that at...
Hi everyone!
I'm not sure if I'm posting this question in the right section. Please don't be mad at me if I'm mistaken.
Can you please help me solve this problem?
Calculate the value of the signal x(t), given its spectrum (see figure in attachment), at the time t=2/W.
Attempted...
how? Where do I get another set of equations? seems as though the node method isn't needed to solve this problem. Do I have to make some adjustments and re-write these equations? If so, what are those adjustments?
\left[ \begin{array}{ c c c }
(\frac{1}{R} + sC) & 0 &...
Please see the pic I've attached. Did I get your suggestion right?
I thought that since the current is not flowing in the upper part of the circuit because of the open circuit represented by the capacitor, I could just eliminate it with a big red "X". This means that for t>0 the initial...