Recent content by hcho88
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Bernouilli's Theorem Question Is my calculation correct?
Can I use the velocity I found (12.52 m/s) from part a) of the question? Assuming I can... theata = 0 degrees horizontal speed = vcos(theata) horizontal speed = 12.52 m/s vertical speed = vsin(theata) vertical speed = 0 m/s H = (2(hsp x vsp)) / g H = 0 ? Hmax = vsp^2 / 2g Hmax = 0...- hcho88
- Post #5
- Forum: Advanced Physics Homework Help
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Bernouilli's Theorem Question Is my calculation correct?
So using projectile motion, like you said, Maximum height = 12m Hmax = (vsine\Theta)^2 / 2g Maximum height is reached when \Theta=45 degrees. So, v = 16.44 m/s Time to reach ground: t = 2v / g t = 2(16.44) / 9.8 t = 3.36 s So, displacement in Y direction: Change in H = (initial...- hcho88
- Post #3
- Forum: Advanced Physics Homework Help
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Calculation: rate, radius, length, density, viscosity, pressure HELP
Homework Statement A patient is to be given a blood transfusion through a tube from a raised bottle to a needle inserted in a vein. The needle has an inner diameter of 0.5mm and is 4.0cm long. If the required blood flow rate is 4.0cm^3/minute, how high should the bottle be placed above the...- hcho88
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- Calculation Density Length Pressure Radius Rate Viscosity
- Replies: 1
- Forum: Advanced Physics Homework Help
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Bernouilli's Theorem Question Is my calculation correct?
Homework Statement I just need someone to check my work. (If what I'm doing is right, if not, tell me where I have gone wrong, and what I should do) Please see attachment for the question. Homework Equations P + 0.5\rhov^2 + \rhogh = constant \rhowater = 1kg/m^3 The Attempt at a...- hcho88
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- Calculation Theorem
- Replies: 5
- Forum: Advanced Physics Homework Help
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Maximum Floating Needle Diameter Calculation
Thank you- hcho88
- Post #6
- Forum: Advanced Physics Homework Help
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Maximum Floating Needle Diameter Calculation
Hold on... I have another theory! Please tell me which one is wrong or right or both are wrong! :S \SigmaF = 0 -W + (\sigmaLcos\theta) + (\sigmaLcos\theta) = 0 W = 2(\sigmaL)cos\theta W = 2 x 0.073 x L x 1 W = 0.146L N And using another formula: P = (2\sigma) / r P = 101325 Pa So, r...- hcho88
- Post #4
- Forum: Advanced Physics Homework Help
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High School Why does stainless steel float when coated with wax?
Thank you.- hcho88
- Post #4
- Forum: Other Physics Topics
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Maximum Floating Needle Diameter Calculation
\SigmaF = 0 -W + (\sigmaL)cos\vartheta + (\sigmaL)cos\vartheta = 0 W = 2(\sigmaL)cos\vartheta W = 2 x 0.073 x L x 1 W = 0.146L N Is this correct? I have absolutely no idea what to do next. Just guessing, please correct me if I'm wrong... Mass of needle = 0.146L/9.8 kg Volume of needle...- hcho88
- Post #3
- Forum: Advanced Physics Homework Help
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Maximum Floating Needle Diameter Calculation
Homework Statement First part of the question was "Why is it possible to float a wax-coated stainless steel needle on the surface of water?" and I've already answered that, but I'm having trouble with the second part of the question, which is: If the surface tension at the interface is...- hcho88
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- Surface Surface tension Tension
- Replies: 5
- Forum: Advanced Physics Homework Help
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High School Why does stainless steel float when coated with wax?
Properties of Matter (Fluids) Why is it possible to float a wax-coated stainless steel needle on the surface of water?- hcho88
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- Float Stainless steel Steel Wax
- Replies: 3
- Forum: Other Physics Topics