Recent content by Hemingway

Thank you! It's hard sometimes when you instinctively know you're doing the wrong thing - but you've just hit an intellectual wall. Thank you so much everybody for helping me out. Many thanks CollinsMark - that would have taken some time to do and I appreciate it.

1/do - 1/.25do = 1/-14 1/.75do = 1/-14 1.3do = 1/-14 ... This still doesn't seem to get to the answer. Could someone show me step by step to how they would get to the answer? I am just too confused. I tried :) I'm finding it difficult to simplify with the inverse. Cheers

Homework Statement An object is located 14.0cm in front of a convex mirror the image is being 7.00cm behind the mirror. A second object twice as tall as the first one is placed in front of the mirror, but at a different location. The image of this second object had the same height as the other...

That was exactly what I was after - thank you very, very much :)

Homework Statement A tennis ball is thrown from ground level with velocity vo directed sin 30 above the horizontal. If it takes the ball 1.0s to reach the top of its trajectory, what is the magnitude of the initial velocity? Homework Equations The initial vertical component of...

oh my gosh. I must have been in a haze of stupidity. I can't believe I couldn't do this. Fresh eyes makes a difference. Thanks to those hanging in there. Oh my - how embarrassing.

basically I cannot see why 2g would not cancel ... and if I knew what I needed I'd recognise how absurd that statement is - but if someone could condescend to show me how step by step I'd be so, so appreciative. Sorry, just having one of those self-confidence draining moments :)

Thanks so much for your reply. As I said above, I am drawing an algebraic blank from how one gets from the first equation in my first post, to the second equation which is: v2 = u2+2g (h0-hf) I know it's elementary, but I know how we get to v2 +2ghf =u2+ 2gh0 but not to v2 = u2+2g (h0-hf)...

okay I worked out how we get to... v2 + 2ghf = u2 +2gh0 v2 = u2 + 2gh0 - 2ghf Can anyone show me why +2gh doesn't cancel by showing me what does happen step by step? Alternatively can someone give me a url website/video that I can look at that will show me the princples as to how this...

Oh yes, that was never in dispute - I believe I prefaced the problem with that statement. I'll take a look. Thanks for the insight tsw99 :)

Okay. Thank you for showing me that. I still don't understand why that is the case... I don't want you to waste your time showing me as you've already taken the time :) but is there a url I can look at to see why the '1/2's don't cancel but instead = 2 ?? I'm just a bit stuck I'm afraid :)

I suppose I need the working from equation (1) to it's manipulation to be equation (2) - as I just don't conceptually understand how the g's don't cancel if the mass cancels...

I'm not exactly sure with what you mean. How would I get a factor of 2? Perhaps there should be a factor of 2 but how do I get that? Once again, I am not sure how there is '2g' in the second equation... :/

Homework Statement A motorcyclist is trying to leap across a canyon. The first cliff is 70m high, she wants to jump to the cliff 35m high. She is traveling 38m/s. Ignoring air resistance, find the speed with which the cycle strikes the ground on the other side. I think (and am very worried...

Thank you very much - I appreciate it.