Recent content by henrik729

actually I did, I wrote it's equal to x2n,n-2 :) No good reason, I just didn't think about using creation and annihilation operators. I talked to some others today who also suggested doing that, so I'm going to try doing it that way later today. But still, it would be nice to be able to...

isn't that one essentially the same as x2n-2,n if I rename n --> n +2? (giving x2n,n+2 = (n+1)(n+2) )

Homework Statement I'm working on problem 3 on page 136 in Landau and Lifgarbagez Quantum mechanics nonrelativistic theory. The problem is to determine the energy levels of an anharmonic linear oscillator with H=H0 + a*x3 + b*x4 (where H0 is the hamiltonian of the harmonic oscillator)...