Recent content by hicsuntdrac0ni

The expressions after the "+...+" are supposed to be the nth term so the n+1 term should be those last two with (n+1) substituted for (n) . Since the first nth terms are x^(n-1)+x^(n-2)*y+...+x*y^(n-2)+y^(n-1) and that is equal to x^n-y^n/(x-y) then I can substitute the...

Homework Statement https://sphotos-b.xx.fbcdn.net/hphotos-prn1/69668_10151632316928154_624610826_n.jpg x^n-y^n = (x-y)*(x^(n-1)+x^(n-2)*y+...+x*y^(n-2)+y^(n-1)) from Number Theory by George E. Andrews Homework Equations The Attempt at a Solution (x^n-y^n)/(x-y) = the sum for the first n...