Induction Proof Statement Help: x^n-y^n = (x-y)*sum

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Homework Help Overview

The discussion revolves around the algebraic identity involving the difference of powers, specifically the expression x^n - y^n and its factorization. The original poster references a source and attempts to manipulate the expression to prove the identity using induction.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the manipulation of the expression (x^n - y^n)/(x - y) and its relation to the sum of powers. There is a focus on substituting terms and verifying the correctness of the sum's components.

Discussion Status

Some participants have pointed out discrepancies in the original poster's approach, specifically regarding the matching of terms in the sum. There is an ongoing examination of the validity of the steps taken and the assumptions made about the terms involved.

Contextual Notes

The discussion is constrained by the need to adhere to the rules of mathematical induction and the proper formulation of the sum involved in the identity. Participants are questioning the accuracy of the terms being used in the proof.

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Homework Statement



https://sphotos-b.xx.fbcdn.net/hphotos-prn1/69668_10151632316928154_624610826_n.jpg x^n-y^n = (x-y)*(x^(n-1)+x^(n-2)*y+...+x*y^(n-2)+y^(n-1))

from Number Theory by George E. Andrews

Homework Equations


The Attempt at a Solution



(x^n-y^n)/(x-y) = the sum for the first n numbers and then i added (x*y^((n+1)-2)+y^((n+1)-1)) which should equal (x^(n+1)-y^(n+1))/(x-y) but i can't figure it out
 
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That's not right. If you let ##n \rightarrow n+1##, you get
\begin{align*}
x^{n+1}-y^{n+1} &= (x-y)(x^{(n+1)-1}+x^{(n+1)-2}y+\cdots+xy^{(n+1)-2}+y^{(n+1)-1}) \\
&= (x-y)(x^n+x^{n-1}y+\cdots+xy^{n-1}+y^{n})
\end{align*} You tacked on the last two terms, but all of the other terms in the sum don't match.
 
vela said:
That's not right. If you let ##n \rightarrow n+1##, you get
\begin{align*}
x^{n+1}-y^{n+1} &= (x-y)(x^{(n+1)-1}+x^{(n+1)-2}y+\cdots+xy^{(n+1)-2}+y^{(n+1)-1}) \\
&= (x-y)(x^n+x^{n-1}y+\cdots+xy^{n-1}+y^{n})
\end{align*} You tacked on the last two terms, but all of the other terms in the sum don't match.

The expressions after the "+...+" are supposed to be the nth term so the n+1 term should be those last two with (n+1) substituted for (n) . Since the first nth terms are x^(n-1)+x^(n-2)*y+...+x*y^(n-2)+y^(n-1) and that is equal to x^n-y^n/(x-y) then I can substitute the x^(n-1)+x^(n-2)*y+...+x*y^(n-2)+y^(n-1) for x^n-y^n/(x-y) and then add x^(n+1)-y^(n+1)/(x-y)
 
I just showed you the first n-1 terms in the sum aren't what you think they're equal to.
 

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