Induction Proof Statement Help: x^n-y^n = (x-y)*sum

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The discussion focuses on the induction proof for the equation x^n - y^n = (x - y) * (x^(n-1) + x^(n-2)y + ... + y^(n-1), as presented in George E. Andrews' "Number Theory." Participants clarify the steps needed to prove the formula by substituting n with n+1 and ensuring that the terms align correctly. The key takeaway is that the last two terms added to the sum must match the nth term, and the substitution process is critical for establishing the proof's validity.

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Homework Statement



https://sphotos-b.xx.fbcdn.net/hphotos-prn1/69668_10151632316928154_624610826_n.jpg x^n-y^n = (x-y)*(x^(n-1)+x^(n-2)*y+...+x*y^(n-2)+y^(n-1))

from Number Theory by George E. Andrews

Homework Equations


The Attempt at a Solution



(x^n-y^n)/(x-y) = the sum for the first n numbers and then i added (x*y^((n+1)-2)+y^((n+1)-1)) which should equal (x^(n+1)-y^(n+1))/(x-y) but i can't figure it out
 
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That's not right. If you let ##n \rightarrow n+1##, you get
\begin{align*}
x^{n+1}-y^{n+1} &= (x-y)(x^{(n+1)-1}+x^{(n+1)-2}y+\cdots+xy^{(n+1)-2}+y^{(n+1)-1}) \\
&= (x-y)(x^n+x^{n-1}y+\cdots+xy^{n-1}+y^{n})
\end{align*} You tacked on the last two terms, but all of the other terms in the sum don't match.
 
vela said:
That's not right. If you let ##n \rightarrow n+1##, you get
\begin{align*}
x^{n+1}-y^{n+1} &= (x-y)(x^{(n+1)-1}+x^{(n+1)-2}y+\cdots+xy^{(n+1)-2}+y^{(n+1)-1}) \\
&= (x-y)(x^n+x^{n-1}y+\cdots+xy^{n-1}+y^{n})
\end{align*} You tacked on the last two terms, but all of the other terms in the sum don't match.

The expressions after the "+...+" are supposed to be the nth term so the n+1 term should be those last two with (n+1) substituted for (n) . Since the first nth terms are x^(n-1)+x^(n-2)*y+...+x*y^(n-2)+y^(n-1) and that is equal to x^n-y^n/(x-y) then I can substitute the x^(n-1)+x^(n-2)*y+...+x*y^(n-2)+y^(n-1) for x^n-y^n/(x-y) and then add x^(n+1)-y^(n+1)/(x-y)
 
I just showed you the first n-1 terms in the sum aren't what you think they're equal to.
 

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