Recent content by Hockey101

Thank you so much!

Ok...so is it because since there is a vertical force and the displacement is horizontal, then that's why work is not being done? So with that in mind, if there was a horizontal force and a horizontal displacement, then there would be work being done on the textbook?

From the site that I am reading from...Work is the "force-displacement product". The formula shows to be: W = FΔs cos θ

1. Hey everyone! I am currently studying for my final exam and I am trying to review work to start out. When I was reading, it gave me an example of where a person is holding a textbook and the person moves the textbook in the horizontal direction. Under the picture they gave an explanation...

So if I plug numbers into those equations, Object A would be 6.26 m/s and Object B would be 4.43 m/s...making Object A with the higher velocity?

I still do not understand...If PE (Gravitational Energy) and KE are equal to each other, then that means KE will equal 9.8J. Considering that both objects have 9.8J as their gravitational energy, then if I plug 9.8 J into KE, both objects come out to be 4.4 m/s. What am I missing?

So what you're saying is to use Ek=1/2mV^2? I do not understand how I am supposed to solve for EK (Kinetic Energy). If I want to find Ek, then I am missing the velocity component in order to figure out Ek. If I'm solving for velocity, then I'm missing the Ek piece. So I do not understand.And...

1. Imagine two objects, A and B, answer the questions that follow based on the conditions given. A= 500g, at 2m, B=1.0kg, at 1m a. Which has a greater Gravitational Energy? Why b. If they are both dropped, which would have a greater velocity impact...