No Work Done on a Textbook: Explanation of Concept

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Homework Help Overview

The discussion revolves around the concept of work in physics, specifically addressing a scenario where a textbook is carried horizontally at a constant velocity. The original poster is trying to understand why no work is done in this situation despite the movement of the textbook.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster questions the relationship between displacement and work, particularly why horizontal movement does not result in work being done. Other participants inquire about the definition of work and its calculation, prompting a discussion on the force-displacement relationship.

Discussion Status

Participants are exploring the definitions and implications of work in the context of the problem. Some have provided insights into the formula for work and the significance of the angle between force and displacement, indicating a productive exchange of ideas without reaching a consensus.

Contextual Notes

There appears to be a focus on understanding the conditions under which work is performed, particularly the role of force direction relative to displacement. The original poster's inquiry suggests a need for clarity on these fundamental concepts.

Hockey101
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1. Hey everyone! I am currently studying for my final exam and I am trying to review work to start out. When I was reading, it gave me an example of where a person is holding a textbook and the person moves the textbook in the horizontal direction. Under the picture they gave an explanation which says: No work is done on a textbook when carried in the horizontal direction at a constant velocity.



2. None



3. Considering Work depends on displacement, I just thought that if you move a textbook up or down and that is displacement, then why can't there be displacement if you move the textbook (or anything) horizontally?
 
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Do you know the definition of "work"? I mean, do you know how to calculate it? What do you get if you use that formula to calculate the work performed moving a book horizontally?
 
From the site that I am reading from...Work is the "force-displacement product". The formula shows to be: W = FΔs cos θ
 
Ok...so is it because since there is a vertical force and the displacement is horizontal, then that's why work is not being done? So with that in mind, if there was a horizontal force and a horizontal displacement, then there would be work being done on the textbook?
 
Right. The ##\theta## in that formula is the angle between the force vector and the displacement vector. So when the force and the displacement are perpendicular, we have ##\cos\theta=\cos\frac\pi 2=0##. When they are parallel, we have ##\cos\theta=\cos 0=1##.
 
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Thank you so much!
 

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