hokhani's latest activity

I think the first alternative is better, but it depends on how you define ΔE and Δt. For ## \Delta t ## it is customary to use the...

I look for the error in the term ##\langle x |P| x \rangle=-i\hbar \frac{\partial}{\partial x} \delta(0)## which seems undefined...

Right, it is undefined. However, still another problem remains: The eigenfunctions of the particle in box, ##\psi_m(x)##, should form a...

So you assume ##~\infty\cdot0=0~## ?

Take ##\psi(x)## to be an arbitrary function and expand the commutator. You will end up with a term proportional to ##\frac{dV}{dx}##...

Finite walls or infinite walls? Start down by writing the Hilbert space, then the two operators. You may discover that the commutator is...

For infinite walls I did that in the post #8.

Very nice separation of the Hamiltonian. If we take ##\psi(x)=\sum_m a_m \psi_m## where ##\psi_m## are the eigenfunction of the...

Does it? We have ##[H,P]=[P^2/2m,P]+[V(x),P]##; the first term is trivially zero but there’s no reason to expect the second one to be...

I would like to know how to calculate the ##[\hat{H}, \hat{P}]## for a particle in a 1D box? At the first glance it seems that they...

The expected value is the average. You always get an energy corresponding to the transition between two eigenstates. The measurement of...

Definitely. I think I got the answer. A distinguished feature of QM is the quantization of quantities but usually this quantization...

I still don't understand what you are looking for. I suggest we'll try to clarify ourselves through a relatively simple example - the...

Thanks, the goal of raising this question was to know, step by step, how quantization manifests itself in practice while the system is...

Only the ground state is stable. An atom in an excited state will emit one or more photons and reduce to the ground state. The same...