Recent content by hops1

Hi guys, I've been trying to figure out how the capacitance of two microstrips, separated a distance d, are influenced by the presence of a dielectric. The dielectric will be a height (h) above the strips and has restricted movement. Using the electric potential I am able to derive a function...

Hi, try using synthetic or long division

Thanks

Thanks I forgot about that theorem. But how do I rule out the negative or positive integers?

Homework Statement Was given a matrix To find the eigenvalues I set up the characteristic equation [-1-x | 7 | -5 ] [-4 | 11-x | -6 ] [-4 | 8 | -3-x] With some dirty work I got this bad boy out, which I'm having trouble factoring -x3+7x2-15x+9Homework Equations...

Thanks a million man.

Hi, thanks for taking your time with me on this. I understand now why it wouldn't work since, the two equations are dependent on each other pretty much. So the eigenvector that corresponds to the given eigenvalue is [1] [1] I actually managed to find some notes online regarding this...

No prob, I'll see how far I can get in the mean time. Hope some more people can give a little input as well

Actually I wanted to ask about that as well. Why does the eigenvalue give a different solution to the equation than if I solve the individual homogenous equation. That's really been confusing me That's why I'm having trouble adapting the other solution as well.

I understand that the Homogenous equation doesn't require the t. I have already gotten the homogenous solution. That's where I get the e-4t from. So found the homogenous solution already using the eigenvalues of the system But the equation given as x1' + 5x1 = x2 requires the solution to...

Hi, As another user stated EE tech isn't that hard, I know some people who have done it, and I'm currently doing EE. And in EE you'll probably fly through most of the EE tech material within your first year. So it can't really be compared. And don't worry too much about the physics...

Now I went back to my initial problem. I'm stuck when trying to get the particular solution, since if you rearrange the matrix x1' + 5x1 = x2 x2' + 3x1 = -x1 So let's say I take the top equation. x1' + 5x1 = x2 I choose a particular solution to test say Cte-4t I end up with...

I think I got it now, I made an error in the particular solution So it should be C1 [1;0]et + C2 [2t;1] et

:frown: I'm worse of than I thought. Well I think et is correct. I'm guessing I messed up in the particular solution for x1 ??I think I found the error in my calculation, will try to run through it again

Ok thanks, I tried the one you posted. I hope I did it right x'=Ax I split it into a system of equations x1' = x1 + 2x2 x2' = x2 x2 could be found easily, since x2' - x2 = 0 Thus follows x2 = C2et Then to find x1 -> x1' - x1 = 2x2 I first find the homogenous solution thus...