I got it! Thanks yall! I do *know* calculus, but I'm really bad with symbols and always overthink. I was severely complicating my derivatives lol, trying to make them much harder than they needed to be. Switching to a,b,c did the trick!
$$A(\omega_d)=\frac{F/m}{\sqrt{(\omega_0^2-\omega_d^2)^2+(\frac{\omega_0}{Q}\omega_d)^2 }}.$$
I think that's right. There was a missing square in your eqn.
No, I can't tell. Should I be able to? I feel like I'm missing something stupidly easy.
It's part of a textbook problem.
It's damped and driven harmonic oscillators - there's lots of equations but I think the relevant ones are x''+γx'+(w0^2)x=F/m(cos(wdt))
and
amplitude = A(wd)=(F/m)/√(((w0^2-wd^2)^2)+((γwd)^2))
but maybe there's others? I just confused in general. I don't know...
Hi everyone, I'm stuck on how to show the peak of the amplitude resonance curve is at wd = w0√(1-1/2Q^2), where Q = w0/γ. My first instinct is to take a derivative of something and set = 0, but what eqn?Help?