thats where I am confused because of the angle in the x direction there is fn and fg and fa but at a 10 degree angle and in the y direction there is fs and fa at a angle so where does the 10 degrees go do i need to split the fa into its x and y components
i did and it mentioned absolutely nothing about angles i under stand the basics i just do not under stand why and where the angle should come into play i have tried another formula- fsMax/FnCos theata but its still not working i used this formula because i believed that my fs max would be the...
yes the box is on a horizontal slope at 10 degrees and i don't know how the normal force is determined
fn=fg but i was not given a mass in the question so i don't get how to determine it without a mass
My work- so far i have tryed to use Fk/Fn=coefficient of static imputing my numbers as 8700/2480=3.50 and 2480/8700=0.29 but neither of these give the correct answer, i don't understand where the angle should be put into my calculation
i tryed putting all the number into that equation but it does not work, i have no clue if i need to include the angle to solve this or not and if i do i have no clue how i would
Hey guys just joined the forum I am currently taking a instrumentation engineering tech. course and it involves a lot of physics so this caught my eye!