Recent content by huffy

nvm I am confused again

whoops, that wouldn't work either because if y was 1/3 than it would be 1/(1/3) which is >>1. ill keep thinking.

So what if we made a quantity that was 1/y. that would guarantee y<<Z if we just want it to be <<1

<< means significantly less than. So id have to make a third quantity that is z-y?

OH. The Vtarget has to be <<1

Perhaps the frequency would be less than 1. Would i be correct in assuming that?

so your variable x would be less than 1, or in the re formatted variable, Vsound would be <<1

is x just a term for frequency in this situation? I am not sure I am following your variables.

No, i haven't learned about power series yet, how does that relate to this?

Homework Statement An audio transmitter and receiver are mounted side by side as shown in the figure. The transmitter emits sound of frequency v. A distant flat plate approaches the instrument at speed Vtarget and the receiver detects sound waves of frequency v' reflected from the target. The...

So to use the information given that the frequency is indeed 261.6 hz, i have to assume that underwater the frequency won't change and that only the speed of the sound waves will change when calculating the wavelength underwater. Would you agree?

Homework Statement Alas, after a sybaritic festival, the cheap upright piano in your fraternity house is found upright at the bottom of the house swimming pool. You decide to play Handel's Water music but first test the sound of middle C (261.6 HZ). The speed of sound in water is...

thank you for your guidance!

Yea I got a much reasonable answer from that. The answer i got for the height is approx 7.34 m. way better that in the 700m zone. Can a water ejection from a pipe really go 7.34m though? I feel like it doesn't pass a common sense check.

Because the pressure should be the same at both places, the start of the ejection and the end of the ejection