Recent content by hula

I've found an answer from a book which states that x(t) = -2/hbar*heaviside(t)*sin(t/hbar*Ek)*exp(-2*pi/T2*t) I'm wondering how to get this answer, because it's a bit different from what I got from MATLAB (the difference is that the solution obtained from the book is in real values, and...

X(w) = 1/(j*(w*hbar-Ek)+(hbar/T2)) - 1/(j*(w*hbar+Ek)+(hbar/T2)) The inverse Fourier transform of the above equation using MATLAB will obtain the following: x(t) = 2*j/hbar*heaviside(t)*sin(t/hbar*Ek)*exp(-t/T2) We can see that the values of x(t) are all imaginary values, however this...

an equation involves an integration. After an inverse Fourier transform of the equation, will the integration limits change? (maybe you can take a look at the attached file) Thanks!