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- Thread starter hula
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Science Advisor

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Consider the function

[tex]F(a) = \int_0^a f(x) \, dx[/tex]

The Fourier-transform will be

[tex]\tilde F(k) = \frac{1}{\sqrt{2\pi}} \int e^{-ika} F(a) \, da

= \frac{1}{\sqrt{2\pi}} \int \int_0^a f(x) e^{-ika} \, dx \, da

[/tex]

If you are lucky you will be able to do the integral in

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