Recent content by huynhtn2

Thank you su much for you help, i got the answer! you are good at helping!

err... 4.62=v1^2+(4.9-v1) 0 = v1^2-v1+0.32 there is a negative under the square root when i use quad formula

from momentum 4.95-v1=v2 energy 21.35 = v1^2 +v2^2 4.62 = v1+v2 4.62=v1+(4.94-v1) i did something wrong

energy (1/2)(8.45)(2.47)^2+19.3= (1/4)mv1^2+(1/4)mv2^2 momentum (8.45)(2.47)=(4.225)v1+(4.225)v2

I finally got it, thanks so much for your help. I know i was annoying so thanks for sticking with helping me.

mv = mv (0.742)(3)=(0.742 +12.8)v? I am confused out of my mind now, please help.

can you please show me how to do this. i would be very grateful.

momentum of rabbit as it leaves plate 2 p=mv = (0.742)(3-0.164) = 2.104 backward momentum of plate p=mv 2.104 =12.8v v= 0.164 I should subtract the velocity from the first equation right?

momentum of rabbit as it leaves plate 2 p=mv = (0.742)(3) = 2.226 backward momentum of plate p=mv 2.226 =12.8v v= 0.173 then take this v and add it to the v from before to get final v?

Yeah... was it a fail?

When the rabbit jumps back to the left plate doesn't it increase the plate 2 velocity when it pushes off from it? or is that wrong?

9.28 =(1/4)mv^2 +(1/4)mv^2 +19.3

Homework Statement A block of mass 8.45 kg in outerspace is moving at 2.47 m/s with no external forces acting on it. After an explosion, the block is split into two parts both having mass equal to half the mass of the original block. The explosion supplies the two masses with an additional...

This is what i tried: m1v1 +m2v2 = m1v1 F + m2v2 F m1v1 + 0 = (m1+m2) vF (0.742)(3.00) = (0.742 + 12.8) vF vF= 0.164 m/s then i added the velocity added when the rabbit jumps back to the left plate p=mv = (0.742)(3) = 2.226 m/s p=mv 1.47 =12.8v v= 0.11 so the total velocity is...

Homework Statement When a bullet strikes a block of wood originally at rest, the bullet becomes embedded into the wood block which travels 1.70 m after the collision. If the mass of the bullet is 5.26 g and the mass of the block is 2.40 kg, what is the speed of the block immediately after the...