Recent content by Iamconfused123
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What Are the Assumptions and Calculations for Sheet of Charge Theory?
To some of these questions I can't find answers on the internet and to some I assume what the answer is but I'd still like to get a confirmation. When I am not given the thickness of the plate, does that mean that the plate is intinitely thin? What is the area of the sheet of charge when the...- Iamconfused123
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- Electric field Gauss law
- Replies: 1
- Forum: Introductory Physics Homework Help
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Centripetal force - Ferris wheel... Opposite results
Thanks everyone🙏, I believe I understand it now. 😅- Iamconfused123
- Post #9
- Forum: Introductory Physics Homework Help
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Centripetal force - Ferris wheel... Opposite results
Thanks for helping me :oldsmile:- Iamconfused123
- Post #5
- Forum: Introductory Physics Homework Help
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Centripetal force - Ferris wheel... Opposite results
I got the correct answers. Thank you very much for that. But, why my approach did not work? was it because the centripetal force is not a real force? just as with a car in a turn, the only force acting on the car is the friction force and no other force, so it would be wrong to write...- Iamconfused123
- Post #4
- Forum: Introductory Physics Homework Help
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Centripetal force - Ferris wheel... Opposite results
I don't understand why am I getting opposite answers. I get 250N for the lowest point and 750 for the highest point. For the highest point: ##F_{net}=F_{cp}+F_{mg}-F_N## and then ##F_N=ma_{cp}+mg = 50*(25/5)+500=750N## because I've been told that ##F_{cp}## always acts towards the center of the...- Iamconfused123
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- Centripetal Force
- Replies: 8
- Forum: Introductory Physics Homework Help
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POWER - different approach, different results
It is exactly as posted. Although it is a translation, "in" which I posted refers to the period from 11th to 12th second. We do not have the word "at" in Croatian so it can be confusing sometimes, but if that was the case I would expect the author to write for "at the 12th second" something like...- Iamconfused123
- Post #23
- Forum: Introductory Physics Homework Help
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POWER - different approach, different results
Got it now. Thank you very very much.- Iamconfused123
- Post #12
- Forum: Introductory Physics Homework Help
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POWER - different approach, different results
In my textbook, one formula for power is P=W/t, where W=Fs and "s" is the path on which force is acting up on the object. In this case wouldn't that be the distance crossed? Assuming no friction, drag or losses of energy- Iamconfused123
- Post #10
- Forum: Introductory Physics Homework Help
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POWER - different approach, different results
yeah, but like, distance at the end of the 12th second or velocity at the end of 12th second, does it matter? if I have the formula for both and both should give back the same result?- Iamconfused123
- Post #9
- Forum: Introductory Physics Homework Help
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POWER - different approach, different results
Thanks, but can you explain to me why this formula works and the other one does not? But without calculus, just words. Also, do you recommend I learn calculus first because I am getting really frustrated by having to guess which formula works and which one does not. And if so, up to what level...- Iamconfused123
- Post #6
- Forum: Introductory Physics Homework Help
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POWER - different approach, different results
Like, I do not know calculus, so I can't understand the reasoning behind it. So I am confused, which method shoud I use for instantaneous power P=Fv or P=Fs/t?- Iamconfused123
- Post #4
- Forum: Introductory Physics Homework Help
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POWER - different approach, different results
No, I want instantaneous power in 12th second. I didn't solve for average power here, I just typed the entire problem. I know how to solve for average, so that is not important. But I do not know how to solve for instantaneous power. I didn't learn calculus so I don't know what the symbols you...- Iamconfused123
- Post #3
- Forum: Introductory Physics Homework Help
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POWER - different approach, different results
Basically, I tried to find the solution by calculating P=Fs/t, where F= 2250 and s is the distance traveled in the 12th second and that result differs from the result I get when I calculate the power using P=Fv. ##F=ma=1500*1.5=2250N## ##s_{12}-s_{11}=...- Iamconfused123
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- Acceleration Power
- Replies: 23
- Forum: Introductory Physics Homework Help
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Elastic potential energy - different methods, different results
Thank you very much. Just figured, Ep is proportional to the square of the elongation of the spring.- Iamconfused123
- Post #3
- Forum: Introductory Physics Homework Help
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Elastic potential energy - different methods, different results
Can someone please tell me where I am wrong? I tried to solve the problem using velocity equation; ##v_{f}^2= v_{i}^{2} + 2as## and got a= 50m/s^2, F= 50 000N and therefore F=kx -> k=50 000N/m because dx=1. But it's not correct. When I do it using conservation of energy I get 100 000N/m. Which...- Iamconfused123
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- Conservation of energy Elastic potential energy Kinetic energy theorem
- Replies: 2
- Forum: Introductory Physics Homework Help