Elastic potential energy - different methods, different results

AI Thread Summary
The discussion centers on the calculation of elastic potential energy and the discrepancies between two methods. The initial approach used the velocity equation, leading to a spring constant of 50,000 N/m, which was deemed incorrect. The correct method applied conservation of energy principles, yielding a spring constant of 100,000 N/m. The error was attributed to the assumption of constant acceleration and force in the first calculation. Ultimately, it was clarified that elastic potential energy is proportional to the square of the spring's elongation.
Iamconfused123
Messages
66
Reaction score
9
Homework Statement
A car of mass 1000 kg hits the spring with a speed of 10 m/s and condenses it by 1 m. If we disregard the friction, what is the resistance constant of the spring?
Relevant Equations
##E_p=\frac{kx^{2}}{2}##, ##E_k=\frac{mv^2}{2}##
Can someone please tell me where I am wrong?
I tried to solve the problem using velocity equation; ##v_{f}^2= v_{i}^{2} + 2as## and got a= 50m/s^2, F= 50 000N and therefore F=kx -> k=50 000N/m because dx=1.

But it's not correct. When I do it using conservation of energy I get 100 000N/m. Which is correct according to the solutions.
##\frac{mv^2}{2}=\frac{kx^2}{2}## -> k=100 000N/m.

Thank you.
 
Physics news on Phys.org
Iamconfused123 said:
Can someone please tell me where I am wrong?
Your first calculation is based on assumption of a constant acceleration / constant force. This assumption is incorrect.
 
  • Like
Likes PeroK and Iamconfused123
Hill said:
Your first calculation is based on assumption of a constant acceleration / constant force. This assumption is incorrect.
Thank you very much. Just figured, Ep is proportional to the square of the elongation of the spring.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top