Recent content by ianrice

Ok right I understand. I was confused. So am I correct with the following next steps: L(p)= ∏(ni+1)(1-p)∑nip2n Then in the next take is to find l(p) which is l(p)=Ln(L(p)) So I end up with: l(p)= Ln(∏(ni+1))+∑niLn(1-p)+2n*Ln(p) Then taking the derivative of dl(p)/dp and...

I got those: ##(1-p)^{n_1}(1-p)^{n_2}(1-p)^{n_3}## = (1-p)∑ni ##p^2p^2p^2## = p2n

So I've collected terms for m=3 and get the following: (n1+1)(n2+1)(n3+1)(1-p)n1(1-p)n2(1-p)n3p2p2p2 So by using your A(1-p)BpC: I think B=∑ni C=2n A is where I'm still stuck. Am I missing something completely I can't seem to figure out how to reduced (n1+1)(n2+1)(n3+1) And to...

The question asks for the general form of the MLE of p. then to compute P(N1,N2...N8). I need help with the general form

Homework Statement 1. An experiment consists of giving a sequences of patients a risky treatment until two have died, and then recording N, the number who survived. If p is the proportion killed by the treatment, then the distribution of N is: P(N=n)=(n+1)(1-p)n p2 1)Find a general formula...

An experiment consists of giving a sequences of patients a risky treatment until two have died, and then recording N, the number who survived. If p is the proportion killed by the treatment, then the distribution of N is: P(N=n)=((n+1)(1-p)^n)p^2 Find a general formula for the MLE for...

The distribution of grades is know to follow a normal distribution, but the mean and variance are unknown. A random sample of 12 students produced the following scores: 59, 84, 68, 93, 49, 77, 82, 75, 81, 58, 70, 80 Find the 90% two-sided confidence interval for the mean score.