Recent content by ice2morrow

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    Calculating Support Forces on a Rigid Beam with Distributed Loads

    So left side is (980)(2.5) = 2450? Why is that? Shouldn't that be center? 2.5 is half the beam. And 980 is the torque on the center.
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    How Far Does a Block Compress a Spring on a Frictionless Surface?

    Homework Statement A 4.0 kg block slides along a frictionless horizontal surface at 5.0 m/s. It runs into and compresses a spring with a spring constant of 200 N/m. How far does it compress the spring before it stops and changes direction? Homework Equations P.E. = 0.5 kx^2 K.E. = 0.5...
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    A 0.300 kg hollow sphere is rolling along a horizontal floor

    So once I have the hypotenuse that's my answer? I see what you did, and I apologize for all the stupid mistakes I'm making. Things are so much simpler when someone holds your hand the entire way... 1.28/sin(30) = 2.56 m
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    Calculating Support Forces on a Rigid Beam with Distributed Loads

    ...Could I get a little more of a step by step? I'm not doing well in this course and have little to no understanding of this material.
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    A 0.300 kg hollow sphere is rolling along a horizontal floor

    Ok so, 3.75 J = (0.3)(9.8)h, h = 1.28 m sin(30) = 1.28/ hypotenuse ---> hypot = 1.28sin(30) = 0.64 m? Did I do that properly?
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    A 0.300 kg hollow sphere is rolling along a horizontal floor

    Ok I get that. So set 3.75 = m*g*h. Solve for h. Once I have that I can find x using sin(30) = h/the hypotenuse. But how do I find that?
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    A 0.300 kg hollow sphere is rolling along a horizontal floor

    Ok so KE before the hill is 1/2(0.3)(5)^2 = 3.75 J. From there I can set that to m*g*sin(30)?...How am I finding the height?
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    Calculating Support Forces on a Rigid Beam with Distributed Loads

    Homework Statement A 5.00 m long rigid beam with a mass of 100.0 kg is supported at each end. An 80.0 kg worker stands on the beam, 4.00 m from the left support. 30.0 kg of brick are stacked on the beam 1.50 m from the left end of the beam. How much upward force does each support exert on...
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    A 0.300 kg hollow sphere is rolling along a horizontal floor

    Any way you could walk me through it, I'm really struggling in this course and my understanding of things is relatively low...
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    A 0.300 kg hollow sphere is rolling along a horizontal floor

    Homework Statement A 0.300 kg hollow sphere is rolling along a horizontal floor at 5.0 m/s when it comes to a 30 degree incline. How far up along the incline does it roll before reversing direction? Homework Equations Kinematics equations? The Attempt at a Solution I didn't...
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    Angular Momentum of a Bar: Calculating Magnitude and Direction

    So what was the I in this problem? I've been given the same problem, but don't know how to calculate the answer.
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    Mechanical Energy and Trajectory

    Thanks a bunch!
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    Mechanical Energy and Trajectory

    I was actually wondering if it would be possible to get the other answer to this question. If you release the rock 1.80 above the ground, with what minimum speed (in m/s) must you throw it? I have no idea how to do this problem.