Recent content by ichigo

All good, if that's not useful, then they won't be giving that to me on the exam. Thankyou very much for your help, I really appreciate it!

Oh, sorry, I meant how to calculate the distance OF the line. I understand how to get displacement

I understand everything except for (I'm guessing) the easiest part. How is the distance calculated on a distance time graph? If the line is curving up and down, how would you be able to tell?

does question 3 mean the resultant force? So its 300-200 =100N?

Okay, my final question: How do you calculate the distance and displacement on a distance-time graph? I know that for a velocity-time graph, distance is the area underneath the line, and displacement is the area underneath the line, but taking the negative into account Is it the same...

for question 3: it has a downward force of 200N. The net force would still be 500N right?

would the answer to question 1 be 8s? if t=Δv/acceleration, =80-0/10= 8 seconds?

Would the answer to question 2 be 200N? If the weight of the object is 200N (20x10), wouldn't the force required to lift it be equal and opposite? Also, for question 3, would the other force be the weight of the object? So 200N, + 300N, is the net force 500N?

Your help would be greatly appreciated 1. If an object is dropped from a cliff, how many seconds will it take to have a speed of 80m/s? would gravity be taken into account? This question seems weird because you usually get given 2 variables to get the third, unless I am missing something...2...