lemme rephrase that, if a object is on the incline say a circular lamina - than the centroid is the height of the object's incline divided by 2?
Cheers!
Hi friends just a quick question,
does the centroid of an object change if it is submerged in a fluid and is on an incline?
Or indeed does the centroid of an object ever change when in a fluid or inclined?
Thanks!
Claudius
Hi friends - I'm at a lost on this particular problem which reads:
a manometer consists of a U-tube, 7mm internal diameter, with vertical limbs with an enlarged upper end of 44mm diameter. the left-hand limb and the bottom of the tube are filled with water and the top of the right hand limb...
Hello friends I am again in need of some asistance,
The Question is as follows:
The pressure head in a gas main at a point 120 m above sea level is equivalent to 180 mm of water. Assuming that the densities of air and gas remain constant and equal to 1.202 kg m^-3 and 0.561 kg m^-3...
Hello friends,
a question about the engineers bending equation,
M/I = E/R = (sigma)/y
so take for example a beam with a rectangular cross section with depth 'b'.
Will y then equal b/2 ? As y is measured from the neutral axis?
Thank you in advance for your time,
Claudius
This would be a great fight. Pacman's offensive ability v Floyd's defensive prowess. If it does happen though the event would be atleast a year off :(.
$50 - That is the market price, but if we are talking about my limit I would proabbly go $100. Is this fight happening soon is it? oh btw I prefer to watch from comfort of my home - you'd have to pay me to go to the stadium.
Hello my friends, so I am once again confused :frown:
Is the second moment of area a universal property of a beam i.e the beams cross section?
So what i mean to say is - if i have a beam and it is curved with a rectangular cross section, and take this same beam and ensure it to be now straight...
If i wanted to calculate I in this problem would it simply be as follows:
I = (pi*P*R^(3)) / (2E) ?
and thus substituting values in if we take
E = 69 GPa
R = 150 mm
P = 0.1 N
we get I = 1.28 *10^(-14)m^(4)
The answer i get in my textbook however reads - 1.63*10^(-28)m^4
Am i...